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Sagot :
The probabilities are P1= 0.9025 , p2= 0.0475 ,P3= 0.0025
the probability that two of them uses seat belt is
P1 (seat belt, seat belt)= (95/100)*(95/100)
= 361/400
=0.9025
the probability that uses seat belt is 95% so the probability that does not uses seat belt is 100% - 95%= 5%
now the probability that one use seat belt is
P2( seat belt ,without seat belt)= (95/100)*(5/100)
=475/10000
=0.0475
now the probability that are not using seat belt
P3(without seat belt ,without seat belt)= (5/100)*(5/100)
=25/10000
=0.0025
Hence ,the probabilities are P1= 0.9025 , p2= 0.0475 ,P3= 0.0025
learn more about of probability here
https://brainly.com/question/15741126
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