Westonci.ca connects you with experts who provide insightful answers to your questions. Join us today and start learning! Get quick and reliable solutions to your questions from a community of experienced experts on our platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

a railway truck of mass 8000 kg travels along a level track at a velocity of 2.5 m s–1 and collides with a stationary truck of mass 12 000 kg. the collision takes 4.0 s and the two trucks move together at the same velocity after the collision. what is the average force that acts on the 8000 kg truck during the collision?

Sagot :

The average force that acts on the 8000 kg truck during the collision is 12000kgm/s.

Impulse is the change in momentum of the body.

Mass, M = 8000kg

Time, t = 4s

Mass, m = 12000kg

Velocity, V = 2.5m/s

Let the Final velocity be v.

Using conservation of momentum to find out the final velocity of the truck,

MV = (M+m)v

8000×2.5 = (8000+12000)×v

v = 1m/s

Now the Initial momentum is MV = 8000×2.5 = 20000kgm/s

Final Momentum is Mv = 8000×1 = 8000kgm/s

Change in Momentum = 20000 - 8000

Change is Momentum = 12000kgm/s

Change is momentum is equal to the average force that acts on the truck from the Newton law of motion.

Hence, the average force that acts on the 8000 kg truck during the collision is 12000kgm/s.

Learn more about Impulse here, https://brainly.com/question/16980676

#SPJ4

Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.