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"a rectangular painting measures 12 inches by 16 inches and is surrounded by a frame of uniform width around the four edges. the perimeter of the rectangle formed by the painting and its frame is 80 inches. determine the width of the frame.\"

Sagot :

the width of the frame is 6 inches

it is a simple one so need to think hard

uniform width of x so the actual perimeter is

2(12 + x + 16 + x)

2(28 + 2x) = 80

28 + 2x = 40

2x = 12

x = 6 inches

learn more of perimeter here https://brainly.com/question/1581707

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