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What is the value of x in the figure below? If necessary, round your answer to
the nearest tenth of a unit.


What Is The Value Of X In The Figure Below If Necessary Round Your Answer To The Nearest Tenth Of A Unit class=

Sagot :

The value of x is 9.5. The square root of 91 is 9.539 but we are asked to round off the answer to the nearest tenth of a unit.

Given the measures of the given triangle are:

length of BD = 7

length of DC = 13

We must ascertain how long AD will be.

Bring the variable to the left side, then move all the other values to the right side in order to determine the value of x. Simplify the values to determine the result.

the length of AD is supposed as x.

hence AD = x

from the theorem : AD² = BD × DC

x² = 7 × 13

x² = 91

x = √91

x = 9.539

but we need to off the value to the nearest tenth of a unit.

hence x = 9.5

Therefore, we get the value for x that is the length of AD as 9.5

Learn more about Triangles here:

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