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Rank the magnitudes of the forces exerted on the following particles from largest to smallest. In your ranking, display any cases of equality. (a) an electron moving at 1Mm/s perpendicular to a 1 -mT magnetic field (b) an electron moving at 1 Mm/s parallel to a 1-mT magnetic field (c) an electron moving at 2 Mm/s perpendicular to a 1-mT magnetic field (d) a proton moving at 1 Mm/s perpendicular to a 1 -mT magnetic field (e) a proton moving at 1 Mm/s at a 45° angle to a 1-mT magnetic field

Sagot :

The correct option is  b) an electron moving at 1 Mm/s parallel to a 1-mT magnetic field.

As we know the Lorentz force, when a charged particle moves under the magnetic field,  it experiences a force which is known as the Lorentz  force, the expression for the Lorentz  force is  

F = qE + qv × B.

Since we are dealing with just a magnetic field the expression  will be

F = qv × B.

    =qvB sinθ

Here q  is the charge of the particle, v is the velocity of the moving particle, B is the magnitude of the magnetic field, and here is the sinθ, where θ is the angle created between  direction of the moving particle and the magnetic field.

Since the direction of the motion of the particle is parallel to the magnetic so  θ =0

which means sin 0°= 0

so, the magnitude of the force is = 0.

To know  more about Lorentz force refer to the link  https://brainly.com/question/24297638?referrer=searchResults.

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