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Sagot :
The correct option is b) an electron moving at 1 Mm/s parallel to a 1-mT magnetic field.
As we know the Lorentz force, when a charged particle moves under the magnetic field, it experiences a force which is known as the Lorentz force, the expression for the Lorentz force is
F = qE + qv × B.
Since we are dealing with just a magnetic field the expression will be
F = qv × B.
=qvB sinθ
Here q is the charge of the particle, v is the velocity of the moving particle, B is the magnitude of the magnetic field, and here is the sinθ, where θ is the angle created between direction of the moving particle and the magnetic field.
Since the direction of the motion of the particle is parallel to the magnetic so θ =0
which means sin 0°= 0
so, the magnitude of the force is = 0.
To know more about Lorentz force refer to the link https://brainly.com/question/24297638?referrer=searchResults.
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