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what would be the molarity of a solution prepared by diluting 250.0 ml of 0.400m sulfuric acid with 1000 ml of water?

Sagot :

The final concentration of sulfuric acid in terms of molarity is 0.08 M.

The molarity of a solution expresses the concentration in terms of the number of moles of solute per liter of solution. Since the volume of the solution increased, the molarity of the solution will change.

First, let us solve for the number of moles of sulfuric acid based on the initial concentration and volume. Volume must be converted to L in order for the units to have consistency.

number of moles = molarity*volume

number of moles = 0.40 M * 250 mL * ( 1 L/1000 mL)

number of moles = 0.10 moles

Then, let us solve for the new concentration by dividing the same number of moles with the new volume. The number of moles remains the same since there is no addition of solute.

final concentration in terms of molarity = number of moles / total volume

final concentration = 0.10 moles / [(250mL+1000mL)*(1L/1000mL)]

final concentration = 0.08 M

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