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in a slap shot, a hockey player accelerates the puck from a velocity of 5 m/s to 30 m/s in the same direction. if the puck moves over a distance of 10 m during this process, what was the acceleration? group of answer choices

Sagot :

bharathparasad577

The acceleration of the puck is 43.75 m/s².

The velocity of an object or particle in uniform motion is defined as the rate at which its direction is changing as seen from a particular angle and as measured by a particular unit of time.

The player's puck accelerates from a velocity of 5 m/s to 30 m/s in the same direction.

The player's puck covers a distance of 10 m during that process.

Therefore,

The initial velocity of the puck is u = 5 m/s

The final velocity of the puck is v = 30 m/s

The distance covered during the period is s = 10 m

Using the equation of motion,

v² - u² = 2as

(30)² - (5)² = 2 × a × 10

900 - 25 = 20 × a

875 = 20 × a

a = 875/20

a = 43.75 m/s²

Learn more about acceleration here:

https://brainly.com/question/460763

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