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A travel agent is booking trips for tourists who travel from New York to Chicago. Tourists have three choices for how to travel from New York to Chicago. They can take an airplane for $350, a bus for $150, or a train for $225. Once they arrive in Chicago, they can travel by van to their hotel for $60 or take a cab for $40. If each option is equally likely to occur, what is the probability that a tourist will spend more than $250 on these 2 legs of the trip?

Sagot :

From the calculation below, the probability that a tourist will spend more than $250 on the 2 legs of the trip is 2/3.

How do we calculate the amount spent using probability?

From the question, the number of possible options available and their total amount is as follows:

Airplane and Van = $350 + $60 = $410

Airplane and Cab = $350 + $40 = $390

Bus and Van = $150 + $60 = $210

Bus and Cab = $150 + $40 = $190

Train and Van = $225 + $60 = $285

Train and Cab = $225 + $40 = $265

From the above, it can be observed that we have a total number of 6 different options available and 4 of the options are more than $250.

Therefore, we have:

Probability of spending more than $250 = Number of options that are more than $250 / Total number of different options = 4/6 = 2/3

Learn more about probability here: https://brainly.com/question/11034287.

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