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15. What is the wavelength of a 1.32 x 10^-6 eV wave?

Sagot :

The wavelength of a 1.32 x 10-⁶ eV wave is 0.939m or 9.39 × 10⁸nm.

How to calculate wavelength?

The wavelength of a wave can be calculated using the following formula:

wavelength = speed ÷ frequency

However, the frequency of the wave needs to be calculated first using the formula as follows:

E = hf

Where;

  • E = energy of the wave
  • h = Planck's constant (6.626 × 10-³⁴J/s)
  • f = frequency

1 electronvolt = 1.602 × 10-19 joule

Hence, 1.32 × 10-⁶ eV is equivalent to 2.11487 × 10-²⁵J.

2.11487 × 10-²⁵J = 6.626 × 10-³⁴ × f

f = 2.11487 × 10-²⁵ ÷ 6.626 × 10-³⁴

f = 3.2 × 10⁸Hz

Wavelength = 3 × 10⁸ ÷ 3.2 × 10⁸

Wavelength = 0.9375 × 10⁰

Wavelength = 0.94m

Therefore, the wavelength of a 1.32 x 10-⁶ eV wave is 0.939m.

Learn more about wavelength at: https://brainly.com/question/13533093

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