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PLEASE PLEASE HELP i have no idea what im doing

the figure shows adjacent angles BAC and CAD given:

mBAD= 129
mBAC= (2x - 1)
mCAD= (3x + 5)

part A: using the angle addition postulate, write and solve an equation for x. show all your work (6 pts)

part B: find the mBAC. show all your work (4 pts)

PLEASE PLEASE HELP I Have No Idea What Im Doing The Figure Shows Adjacent Angles BAC And CAD Given MBAD 129 MBAC 2x 1 MCAD 3x 5 Part A Using The Angle Addition class=

Sagot :

devishri1977

Answer:

x = 25

∠BAC = 49°

Step-by-step explanation:

Part A)

∠BAC + ∠CAD = ∠BAD

 2x - 1 + 3x + 5 = 129

  2x + 3x - 1 + 5 = 129

Combine like terms,

  5x + 4 = 129

Subtract 4 from both sides,

        5x = 129- 4

        5x = 125

Divide both sides by 5

          x = 125 ÷ 5

          [tex]\sf \boxed{\bf x = 25}[/tex]

Part B) Finding the ∠BAC:

To find ∠BAC, substitute the value of x= 25 in (2x - 1).

∠BAC = 2x - 1

          = 2*25 - 1

          = 50 - 1

         = 49°

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