At Westonci.ca, we connect you with the best answers from a community of experienced and knowledgeable individuals. Get detailed answers to your questions from a community of experts dedicated to providing accurate information. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.
Sagot :
The number of distinct values that we can draw(with replacement) is;
= [tex]\frac{ ((2n-1)!)}{ n!(n -1)! }[/tex]
Here,
The given set is = {1, 2, 3, ……, n}
n number of drawn from this set with replacement.
Then we have to find number of distinct values that we can draw.
What is combination?
The field of mathematics concerned with problems of selection, arrangement, and operation within a finite or discrete system.
Now,
The given set is = {1, 2, 3, ……, n}
n number of drawn from this set with replacement.
Since, we know we draw p things from q with replacement then
Number of ways = [tex]^{p+q-1} C_q[/tex]
Here number of element in the set = n
And number of element we have to draw with replacement = n
Therefore, number of distinct values that we can draw
= [tex]^{n+n-1} C_n[/tex]
= [tex]^{2n-1} C_n[/tex]
= [tex]\frac{(2n-1)!}{n!(2n -1 - n)!}[/tex]
= [tex]\frac{((2n-1)!)}{n!(n -1)!}[/tex]
Hence, The number of distinct values that we can draw(with replacement) is;
= [tex]\frac{ ((2n-1)!)}{ n!(n -1)! }[/tex]
To learn more about combination visit:
https://brainly.com/question/11732255
#SPJ4
Visit us again for up-to-date and reliable answers. We're always ready to assist you with your informational needs. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.
