Using the knowledge of computational language in python we can write the code as function, daysbewteen, which returns an integer representing the numbers of days between two dates.
#include <iostream>
using namespace std;
int daysInMonth(int month, int year) //function to know the days in a month
{
//array to store the days of each month for a non-leap year
int a1[] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
//array to store the days of each month for a leap year
int a2[] = {31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
if(((year % 4 == 0) && (year % 100 != 0)) || (year % 400 == 0)) //if the year is a leap year
return a2[month-1]; //value from a2 array is returned
else //else if the year is not a leap year
return a1[month-1]; //value from a1 array is returned
}
int daysBetween(int y1, int m1, int d1, int y2, int m2, int d2) //function definition
{
int days = 0; //days is initialized to zero
for(int i = y1; i <= y2; i++) //for each year from y1 to y2 loop repeats
{
if(i == y1) //if i equals to y1
{
days = days + daysInMonth(m1, y1) - d1; //for m1 days is calculated and subtract d1 from that
for(int j = m1+1; j <= 12; j++) //from the months starting m1+1
{
days = days + daysInMonth(j, i); //days in each month is added to days variable
}
}
else if(i == y2) //if i equals to y2
{
days = days + d2; //d2 is added to days
for(int j = 1; j < m2; j++) //we can only check upto m2-1 month
days = days + daysInMonth(j, i); //days in each month is added to days
}
else //else
for(int j = 1; j <= 12; j++) //for each month in that year
days = days + daysInMonth(j, i); //days in that month is added to days
}
return days; //days is returned
}
int main() //main function
{
int y1, m1, d1, y2, m2, d2; //variable declarations
cin >> y1 >> m1 >> d1 >> y2 >> m2 >> d2; //reads the input
cout << daysBetween(y1, m1, d1, y2, m2, d2); //calls the function and prints returned value
return 0;
}
See more about C++ at brainly.com/question/19705654
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