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what is the symbol for the element with an electron configuration of 1s^22s^22p^31s 2 2s 2 2p 3 1, s, squared, 2, s, squared, 2, p, cubed?

Sagot :

The correct answer is Nitrogen.

From the given question the electronic configuration of the element is given as:

1s²2s²2p³

hence, we know that the maximum no of electrons in the sub-shell

s= 2

p=6

while in this p has only 6 electrons.

Thus by counting the number of electrons in each sub-shell we can know the atomic number as several electrons in an atom is equal to the atomic number of the atom.

thus, the no of electrons present is- 2+2+3= 7

For, 7 electrons the element present will be nitrogen with atomic number 7.

To learn more about electronic configuration visit the ink:

https://brainly.com/question/13497372?referrer=searchResults

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