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Sagot :
By angular speed, the spring constant is 63.21 N/m.
We need to know about the angular speed of harmonic oscillation. the angular speed can be determined as
ω² = k / m
where ω is angular speed, k is spring constant, and m is the mass.
The angular speed can be calculated by
ω = 2π/T
Hence,
ω² = k / m
(2π/T)² = k / m
where T is period.
From the question above, we know that:
m = 0.4 kg
T = 0.5 s
By substituting to the equation, we get
(2π/T)² = k / m
(2π/0.5)² = k / 0.4
158.04 = k / 0.4
k = 63.21 N/m
Find more on angular speed at: https://brainly.com/question/6860269
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