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consider a certain type of nucleus that has a decay rate constant of 0.0250 min-1. calculate the time required for the sample to decay to one-fourth of its initial value.

Sagot :

It takes approximately 55 mins for the sample to decay to one - fourth of its original amount.

In the given statement is:

λ = 2.5 x 10^-2 [tex]min^{-1}[/tex]is the rate constant of the nucleus

To solve this problem, we use

N(t) = [tex]N_{0}[/tex]e^-λt

and since we are looking for the time it takes to decay the nucleus to one -fourth of its original amount, we set

N(t) = 1/4 [tex]N_{0}[/tex] = 0.25[tex]N_{0}[/tex]

We can substitute this in the decay equation:

0.25[tex]N_{0}[/tex] =[tex]N_{0}[/tex] e^-λt

Cancel the like terms

0.25 = e ^-λt

Take the natural logarithm of both sides:

㏑(0.25) =㏑(e^-λt)

㏑(0.25)= -λt

Solve for the time t:

t = - ㏑(0.25)/λ

Substitute the given rate constant :

t = ㏑(0.25) / 2.5 x 10^-2 [tex]min^{-1}[/tex]

t = -1.3863 /2.5 x 10^-2 [tex]min^{-2}[/tex]

t = 55.452mins

It takes approximately 55 mins for the sample to decay to one - fourth of its original amount.

Learn more about the Decay of Nucleus at:

https://brainly.com/question/14667624

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