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what is the repulsive force between two pith balls that are 13.5 cm apart and have equal charges of 44.0 nc?

Sagot :

One pith ball's charge, q1, is equal to 30 nC, or 30x10-9C.

the second pith ball's charge, q2 = -30n c= -30x 10-9 c

They are separated by d=8 cm, or 8x10-2 metres.

They repel one another by a force of F = (81/64) x 10-3.

F = 1.266x10^-3 N

Is the force of gravity repellent?

The gravitational force is solely an attracting one in both the General Theory of Relativity and Newton's theory of gravity. But quantization of gravity demonstrates that there are opposing gravitational forces as well.

A force between two or more opposite or different charges is called attraction. Two charges that are at odds with one another are attracted to one another. A force between two or more like or comparable charges is called repulsion. Two identical charges separate themselves.

learn more about repulsive force refer

https://brainly.com/question/455976

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