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the area of the rectangle is 14yd squared and the length of the rectangle is 3yds leass than twice the width

Sagot :

The dimensions of the rectangle are:

  • Length = 7/2 yd
  • Width = 4 yd
  • Total area = 14 yd²

What is the area?

  • The quantity area expresses the extent of a region on a plane or curved surface.
  • Surface area refers to the area of an open surface or the boundary of a three-dimensional object, whereas the area of a plane region or plane area refers to the area of a shape or planar lamina.

To find the dimensions of the rectangle:

Let,

  • Area = A = 14
  • Width = w
  • Length = 2w-3
  • A = lw
  • A = (2w-3)w

Extend the area equation as follows:

  • A = 2w2-3w

Rearrange:

  • 2w2 - 3w - A = 0

Substitute known information for A:

  • 2w2 - 3w - 14 = 0

To solve quickly, factor the left side (or use the quadratic formula):

  • (w+2)(w - 7/2) = 0

The factorial solutions for w are -2 and 7/2.

Assuming this is a genuine rectangle, the width must be positive.

As a result, the length is:

  • 2(7/2) - 3

That is,

  • 7 - 3 = 4

Therefore, the dimensions of the rectangle are:

  • Length = 7/2 yd
  • Width = 4 yd
  • Total area = 14 yd²

Know more about the area here:

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The complete question is given below:
The area of a rectangle is 14 yd², and the length of the rectangle is 3 yd less than double the width. find the dimensions of the rectangle.