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a man jogs at a speed of 1.5 m/s. his dog waits 2.5 s and then takes off running at a speed of 3.3 m/s to catch the man. how far will they have each traveled when the dog catches up with the man?

Sagot :

By the velocity, they will travel 6.875 m and the dog catches the man at 2.08s.

We need to know about velocity to solve this problem. Velocity can be determined as the distance traveled divided by time interval. It can be written as

v = s / t

where v is velocity, s is distance and t is the time interval.

From the question above, we know that.

v man = 1.5 m/s

v dog = 3.3 m/s

to = 2.5s

Determine the distance traveled by man when the dog waits

so = vman . to

so = 1.5 x 2.5 = 3.75 m

Find the man's total distance

total distance = distance after dog run + distance when the dog waits

total distance = vman . t + 3.75

We know that the total distance by man's will be caught by the dog, Thus

total distance = vman . t + 3.75

v dog . t = 1.5t + 3.75

3.3t = 1.5t + 3.75

1.8t = 3.75

t = 2.08 s

Find total distance

total distance = vdog . t

total distance = 3.3 x 2.08

total distance = 6.875 m

Find more on velocity at: https://brainly.com/question/25749514

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