At Westonci.ca, we connect you with the answers you need, thanks to our active and informed community. Discover reliable solutions to your questions from a wide network of experts on our comprehensive Q&A platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.
Sagot :
The cost of the Coca-Cola can will be $1 in the year 2000.
Given that the cost of a can of Coca-Cola can in 1960 = $0.10
The function which models the cost of a Coca-Cola by year 't' is
c(t) = [tex]0.10e^{0.0576t}[/tex].
Here, 't' denotes the number of years since 1960.
c(t) is an exponential function.
We have to find the year in which the cost of a can will be $1.
So substitute c(t) = 1, we get,
1 = [tex]0.10e^{0.0576t}[/tex]
⇒ [tex]10 = e^{0.0576t}[/tex]
We have, [tex]ln(e^x) = x[/tex] .
Taking logarithm on both sides, we get,
log(10) = 0.0576t
⇒ [tex]t=\frac{ln(10)}{0.0576}[/tex] = 39.97 ≈ 40 years .
Thus the cost of a can of Coca-Cola will be $1 in the year, 1960 + 40 = 2000.
The question was incomplete. Find the complete question at:
The cost of a can of Coca-Cola in 1960 , was $0.10. The function that models the cost of a Coca-Cola by year is C(t)=0.10e^(0.0576t) , where t is the number of years since 1960 . In what year is it expected that a can of Coca-Cola will cost $1.00 ?
Learn more about exponential functions at https://brainly.com/question/23049613
#SPJ4
Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.
