Answered

Welcome to Westonci.ca, where finding answers to your questions is made simple by our community of experts. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

If a circle has equation (x-3)^2 + (y+1)^2 = 49, what is it’s domain?
I’m forgetting everything from algebra

Sagot :

MrRoyal

The domain of the circle is [-4, 10]

How to determine the domain of the circle?

The circle equation is given as:

(x - 3)^2 + (y + 1)^2 = 49

Express 49 as 7^2

So, we have

(x - 3)^2 + (y + 1)^2 = 7^2

The general circle equation is

(x - a)^2 + (y - b)^2 = r^2

Where the domain is

Domain = [a ± r]

So, we have

Domain = [3 ± 7]

Evaluate

Domain = [3 - 7, 3 + 7]

This gives

Domain = [-4, 10]

Hence, the domain of the circle is [-4, 10]

Read more about domain at:

https://brainly.com/question/2264373

#SPJ1

We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.