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Simplify each expression for x=6 a. 12x^0(x^-4) b. 14(x-2)

Sagot :

After solving the expressions we get the value for each of it as:

a. 1/108

b. 7/18

Given:

a. 12x⁰(x⁻⁴)

Apply the multiplication property of exponents.

when variables multiply, the powers are added.

12x⁰⁻⁴

12x⁻⁴

substitute the value of x = 6 in the above term.

12(6)⁻⁴

12 × 1/6⁴

12 × 1/1296

1/108

b. 14(x⁻²)

The algebraic technique for resolving simultaneous linear equations is called the substitution method. The value of a variable from one equation is substituted in the second equation in this procedure, as the name implies.

directly substitute the value of the x in the expression.

14(6)⁻²

14 × 1/6²

14 × 1/36

7/18

hence after evaluating expressions we get the values as 1/108 and 7/18.

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