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according to the fundamental theorem of algebra, how many roots exist for the polynomial function? (9x 7)(4x 1)(3x 4)

Sagot :

maryamkincsem

3 number of roots exist for the polynomial function.

Step-by-step explanation:

As we know that the polynomial can only have exact number of roots as high as the degree of that polynomial is.

We can also prove it. Assume there is a polynomial

(x+2)(x+3) =0

Here the degree of the polynomial is 2 and the number of possible solutions are also 2. As it is evident that x is either equal to -2 or -3.

From the given condition,

(9x + 7)(4x + 1)(3x + 4)

we know that the degree of the polynomial is 3 because after expansion it becomes,

108x^3 + 255 x^2 +169x + 28 =0

Since, highest power of the variable is 3. Its degree is 3.

Therefore, possible number of roots that exist for the polynomial function are 3.

You can learn more about number of roots of polynomials from
https://brainly.com/question/10702726
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