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Sagot :
90.0 g of vanadium (V) oxygen sample has 1.50 x 10 24 oxygen atoms.
To determine the number of oxygen atoms in a vanadium oxide sample, the following steps must be made.
Step 1: Convert the mass of vanadium(V) oxide to mol of vanadium(V) oxide
mol vanadium(V) oxide = mass / molar mass
mol vanadium (V) oxide = 90.0 g / 181.88 g/mol
mol vanadium (V) oxide = 0.49483 mol
Step 2: Convert mol of vanadium (V) oxide to moles of oxygen using mole ratio
mol oxygen = mol vanadium (V) oxide * mole ratio O / mol V2O5
mol oxygen = 0.49483 mol * 5 mol O / mol V2O5
mol oxygen = 2.47416 mol O
Step 3: Convert to oxygen atoms using Avogadro's number
atoms oxygen = mol oxygen * 6.02214 x 10 23 atoms O /mol O
atoms oxygen = 2.47416 mol O * 6.02214 x 10 23 atoms O/mol O
atoms oxygen = 1.48997 x 10 24 atoms or 1.50 x 10 24 atoms O
To learn more about Avogadro's number, please refer to the link https://brainly.com/question/859564.
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