Explore Westonci.ca, the top Q&A platform where your questions are answered by professionals and enthusiasts alike. Discover a wealth of knowledge from experts across different disciplines on our comprehensive Q&A platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
The electric field at a midpoint is 1.425 x 10⁴ N/C.
We need to know about the electric fields to solve this problem. The electric field produced by a single-point positive charge is a radial field, whose strength is given by the equation
E = k.Q/r²
where E is the electric field, Q is the charge and r is the radius.
From the question above, we know that
k = 9 x 10⁹ Nm²/C²
Q1 =e = 1.6 x 10¯¹⁹ C
Q2 = e = 1.6 x 10¯¹⁹ C
x = 897 nm = 8.97 x 10¯⁷ m
from midpoint (r = 4.495 x 10¯⁷ m)
The electric field radially outward from proton to electron so that the total electric field between the charges will be added up.
Etotal = E1 + E2
Etotal = k.e/r² + k.e/r²
Etotal = 2. k.e/r²
Etotal = 2 x 9 x 10⁹ x 1.6 x 10¯¹⁹/(4.495 x 10¯⁷)²
Etotal = 1.425 x 10⁴ N/C
Find more on electric field at: https://brainly.com/question/14372859
#SPJ4
Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.
