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A 3.00- L flask is filled with gaseous ammonia, NH3 . The gas pressure measured at 25.0 ∘C is 2.55 atm . Assuming ideal gas behavior, how many grams of ammonia are in the flask?
Express your answer to three significant figures and include the appropriate units.

Sagot :

Considering the ideal gas law, the mass of ammonia is 5.321 grams.

Ideal gas law

An ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of gases:

P×V = n×R×T

Mass of ammonia

In this case, you know:

  • P= 2.55 atm
  • V= 3 L
  • n= ?
  • R= 0.082 [tex]\frac{atmL}{molK}[/tex]
  • T= 25 C= 298 K

Replacing in the definion of ideal gas law:

2.55 arm× 3 L = n×0.082 [tex]\frac{atmL}{molK}[/tex]× 298 K

Solving:

n= (2.55 arm× 3 L)÷ (0.082 [tex]\frac{atmL}{molK}[/tex]× 298 K)

n= 0.313 moles

Being the molar mass of ammonia 17 g/mole, the mass can be calculated as:

mass of ammonia= 0.313 moles× 17 g/mole

Solving:

mass ammonia= 5.321 g

Finally, the mass of ammonia is 5.321 grams.

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