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Sagot :
The broglie wavelength is 9.27 x 10¯³⁵ meter.
We need to know about de Broglie's wavelength to solve this problem. Broglie's wave equation is the following :
λ = h / (m.v)
where λ is the wavelength, h is Max Planck constant 6.62x10⁻³⁴ J.s, m is the mass and v is velocity.
From the question above, we know that:
m = 231 gram = 0.231 kg
v = 34 m/s
By substituting the parameter, we get :
λ = h / (m.v)
λ = 6.62x10⁻³⁴ / (0.21 x 34)
λ = 9.27 x 10¯³⁵ m
Hence, the broglie wavelength is 9.27 x 10¯³⁵ meter.
Learn more about de broglie wavelength at: https://brainly.com/question/16595523
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