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Factor completely.
100-9x²

someone help please


Sagot :

Answer:

[tex](10+3x)(10-3x)[/tex]

Step-by-step explanation:

[tex]100-9x^2\\\sqrt{100} =10\\\sqrt{9} =3\\3*-3=-9\\\sqrt{x^2} = x \\(10-3x)(10+3x)[/tex]

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Considering both terms are perfect squares, factor using the difference of squares formula:

[tex]a^2-b^2=(a+b)(a-b)[/tex]

In this situation, a = 10 and b = 3x. With this, now plug in your data into the formula.

(10 + 3x) (10 - 3x)

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Hope this helps! If so, lmk! Thanks and good luck!