Discover answers to your most pressing questions at Westonci.ca, the ultimate Q&A platform that connects you with expert solutions. Connect with professionals on our platform to receive accurate answers to your questions quickly and efficiently. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.
Sagot :
The quadratic equation with a repeated root is:
8*x^2 - 32*x +32
And the repeated root is x = 2
What is the repeated root?
For a quadratic equation:
0 = a*x^2 + b*x + c
We define the discriminant as:
D = b^2 - 4ac
If D = 0, we have only one real root (or two repeated roots). Then we just need to see which of the given quadratic equations has a discriminant of zero.
1) -x^2 + 18x + 81
The discriminant is:
D = 18^2 - 4*(-1)*81 = 648
2) 3x^2 - 6x + 9
The discriminant is:
D = (-6)^2 - 4*3*9 = -72
3) 8*x^2 - 32*x +32
The discriminant is:
D = (-32)^2 - 4*8*32 = 0
So this is the one with a discriminant of zero.
The roots are given by:
8*x^2 - 32*x +32 = 0
Using Bhaskara's formula we will get:
x = (- (-32) ± √( (-32)^2 - 4*8*32))/(2*8)
x = (32/16) = 2
The repeated root is x = 2
If you want to learn more about quadratic equations:
https://brainly.com/question/1214333
#SPJ1
We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.