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How do I do this equilibrium constant problem?[Ap Chem]

How Do I Do This Equilibrium Constant ProblemAp Chem class=

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pstnonsonjoku

The equilibrium constant of the second reaction is 2.0 * 10^-3.

What is the equilibrium constant?

Let us recall the the equilibrium constant shows the extent to which reactants are converted into products in a reaction. A large positive value of the equilibrium constant shows that most of the reactants is converted into products.

Now we can see that the second reaction is obtained when the first reaction is halved and inverted. This now means that we can write;

K2 = 1/K1^1/2

K2 = 1/√K1

K2 = 1/(2.5 * 10^5)

K2 = 2.0 * 10^-3

Learn more about equilibrium constant:https://brainly.com/question/10038290

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