The solutions associated with each case are listed below:
- 3 · x + 2
- 2 - x
- 2 · x² + 4 · x
- 1 / 2 + 1 / x
- 2 · x + 2
- 2 · x + 4
- x + 4
- 4 · x
- - 8
- 2
How to use operations between functions and evaluate resulting expressions
According to the statement, we find that the two functions are f(x) = x + 2 and g(x) = 2 · x and we are asked to perform on the functions to obtain all resulting expressions and, if possible, to evaluate on each case:
Case 1
(f + g) (x) = f (x) + g (x) = (x + 2) + 2 · x = 3 · x + 2
Case 2
(f - g) (x) = f (x) - g (x) = (x + 2) - 2 · x = 2 - x
Case 3
(f · g) (x) = f (x) · g (x) = (x + 2) · (2 · x) = 2 · x² + 4 · x
Case 4
(f / g) (x) = f (x) / g (x) = (x + 2) / (2 · x) = 1 / 2 + 1 / x
Case 5
(f ° g) (x) = f [g (x)] = 2 · x + 2
Case 6
(g ° f) (x) = g [f (x)] = 2 · (x + 2) = 2 · x + 4
Case 7
(f ° f) (x) = f [f (x)] = (x + 2) + 2 = x + 4
Case 8
(g ° g) (x) = g [g (x)] = 2 · (2 · x) = 4 · x
Case 9
(g ° g) (- 2) = 4 · (- 2) = - 8
Case 10
(f ° f) (- 2) = - 2 + 4 = 2
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