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Write in point slope form an equation of the line through the pair of points.
(9,8) and (6,1)
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What is an equation of the line in point-slope form? Show your work.
A.) y - 8 = -7/3(x - 9)
B.) x - 8 = 7/3(y - 9)
C.) y = -7/3x - 13
D.) y - 8 = 7/3(x-9)

Sagot :

I think it’s A I solved it and that was my answer.

Answer:

d) y - 8 = 7/3(x - 9)

Explanation:

[tex]\sf point-slope\:form :[/tex]

[tex]\sf y - y_1 = m(x - x_1) \ \ where \ (x_1, y_1), \ (x_2, y_2) \ are \ points \ and \ m \ the \ slope[/tex]

Find the slope:

[tex]\sf slope: \dfrac{y_2 - y_1}{x_2- x_1} \ \ where \ (x_1 , \ y_1), ( x_2 , \ y_2) \ are \ points[/tex]

[tex]\sf \rightarrow slope\ (m) : \dfrac{1-8}{6-9} = \dfrac{-7}{-3} = \dfrac{7}{3}[/tex]

Find the equation:

in point slope form:

[tex]\sf y - 8 = \dfrac{7}{3} (x - 9)[/tex]

[tex]\sf y = \dfrac{7}{3} x - 21+8[/tex]

in slope intercept form

[tex]\sf y = \dfrac{7}{3} x -13[/tex]