Answered

Welcome to Westonci.ca, the ultimate question and answer platform. Get expert answers to your questions quickly and accurately. Join our Q&A platform and connect with professionals ready to provide precise answers to your questions in various areas. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

Solve the inequality and express your answer in interval notation.
X^2+8x+5<0

Solve The Inequality And Express Your Answer In Interval Notation X28x5lt0 class=

Sagot :

Answer: (-4-[tex]\sqrt{11}[/tex], -4+[tex]\sqrt{11}[/tex]) ==> B

Step-by-step explanation:

x^2+8x+5<0

x^2+8x+16-11<0

(x+4)^2-11<0

(x+4)^2<11

x+4<[tex]\sqrt{11}[/tex]

x<-4+[tex]\sqrt{11}[/tex]

x+4>-[tex]\sqrt{11}[/tex]

x>-4-[tex]\sqrt{11}[/tex]

(-4-[tex]\sqrt{11}[/tex], -4+[tex]\sqrt{11}[/tex]) ==> B

Remember, the solution doesn't include the x values -4-[tex]\sqrt{11}[/tex] and -4+[tex]\sqrt{11}[/tex]  since if they were plugged in x^2+8x+5, the expression would equal 0. The expression is supposed to be LESS than 0, not equal to 0.

siakim

Answer:

Answer: (-4-\sqrt{11}11 , -4+\sqrt{11}11 )

x^2+8x+5<0

x^2+8x+16-11<0

(x+4)^2-11<0

(x+4)^2<11

x+4<\sqrt{11}11

x<-4+\sqrt{11}11

x+4>-\sqrt{11}11

x>-4-\sqrt{11}11

(-4-\sqrt{11}11 , -4+\sqrt{11}11 ) 

Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.