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Find the equation the line with a slope of 2 and that passes
through the point (1, 6).
Enter your answer in slope-intercept form, y = mx + b

Sagot :

rvkacademic

Answer:

y = 2x +4

Step-by-step explanation:

Equation of a line in slope-intercept form is

y = mx + b

where m is the slope and b is the y-intercept, the point at which the line crosses the y axis (at x = 0)

Given slope is 2 we get the equation as

y = 2x + b

We have to solve for b by plugging in the x and y values for point(1,6)

Thus we get y = 6 = 2(1) + b

Or 6 = 2 + b

b= 6-2 = 4

Equation in slope-intercept form is

y = 2x +4

StargazingWithJoy

Hi!

Apply the Point-Slope formula:

  • [tex]\textsl{y-y1=m(x-x1)}[/tex]

◈Where:

  • y₁ -> the y-coordinate of the point
  • m -> slope
  • x₁ -> x-coordinate

◈We know that:

  • y₁ -> 6
  • m -> 2
  • x₁ -> 1

◈Plug in the values:

  • [tex]\boldsymbol{y-6=2(x-1)}[/tex]
  • (simplify) [tex]\boldsymbol{y-6=2x-2}[/tex]
  • (add 6 to both sides) [tex]\boldsymbol{y=2x+4}[/tex]

[tex]\bigstar\textsf{\textbf{Solution: \boxed{\textsf{\textbf{2x+4}}}}}[/tex]

Have a great day!

I hope this helped!

-stargazing

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