(ii) An element A is in period 3 and it loses three electrons to form an ion. (a) Write the electronic configuration of atom A. (B) Calculate the number of atoms in element A if it has a mass of 27.0g.[5.022x10^23] (c)What is the name of the ion formed?

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03-09-2022
Chemistry

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(ii) An element A is in period 3 and it loses three electrons to form an ion. (a) Write the electronic configuration of atom A. (B) Calculate the number of atoms in element A if it has a mass of 27.0g.[5.022x10^23] (c)What is the name of the ion formed?

Sagot :

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tripatsingh039 tripatsingh039 · Answer 1 · 2022-09-08T19:51:13-04:00

The aluminum ion, Al3+, is produced when an aluminum atom loses three electrons, and the magnesium ion, Mg2+, is produced when a magnesium atom loses two electrons. Atoms of elements that lose electrons gain a positive charge.

The three valence electrons in aluminum are lost, forming a cation with a positive charge of three: These cations have names that correspond to the metals that they are made of the octet rule is not always followed by transition elements and the metals to their right; frequently, they create more than one cation. Ionization is the process by which ions are created when an atom or molecule gains or loses an electron.

Learn more about Aluminum here-

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(ii) An element A is in period 3 and it loses three electrons to form an ion. (a) Write the electronic configuration of atom A. (B) Calculate the number of atoms in element A if it has a mass of 27.0g.[5.022x10^23] (c)What is the name of the ion formed?​

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(ii) An element A is in period 3 and it loses three electrons to form an ion. (a) Write the electronic configuration of atom A. (B) Calculate the number of atoms in element A if it has a mass of 27.0g.[5.022x10^23] (c)What is the name of the ion formed?