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Two batteries of 7 V and 13 V with the internal resistances 1 ohm and 2 ohm respectively are connected in parallel with a resistance of 12 22. Find the current through each branch of the circuit and the potential difference across 12 ohm resistance.​

Sagot :

the current through each branch of the circuit and the potential difference across 12-ohm resistance is 0.711A

The flow of charge is the current. A component is used to measure current. Potential difference is measured between two points on either side of a component because it represents the energy transferred between two points in a circuit.

-12(I1+I2) -1I1+7=0

12(I1+I2) +1I1=7

For the loop

-12(I1+I2) -2I=13

From 1&2

2I -I1=13-7=6

I1=2I2-6

The crucial distinction between current and voltage. Current in the circuit flows due to voltage, which is the potential difference between two locations in an electric field. The term "current" refers to the rate at which electrons are moving.

I2=85/38=2.237A

I1=2I 2-6

I1=2 x 85/38-6=-1.526A

I=I1+I2=-1.526+2.237=0.711A

Potential difference across 12-ohm resistance

V=0.711 x 12=8.53 v

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