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Two positive integers that differ by 9 are in the ratio of 8 to 11. What is the value of the smaller of the two numbers?​

Sagot :

hnori22003

The numbers are 24 and 33 so the smaller one is 24

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Answer:

24 and 33 are the numbers among which 24 is the smallest.

Step-by-step explanation:

Let one positive integer be x, then another will be x - 9

Solve:

[tex]\sf \dfrac{x-9 }{x} = \dfrac{8}{11}[/tex]

cross multiply

[tex]\sf 11x-99= 8x[/tex]

collect like terms

[tex]\sf 11x-8x = 99[/tex]

simplify

[tex]\sf 3x = 99[/tex]

divide both sides by 3

[tex]\sf x = 33[/tex]

As the integer is positive, x = 33, then another will be 33 - 9 = 24.

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