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Sagot :
The confidence limits for the proportion of consumers motivated by advertising in the population, given a confidence level equal to 0.95. is; CI = (0.47, 0.77)
How to find confidence Interval of Proportions?
We are given;
Sample Size; n = 60
sample proportion; p' = 65% = 0.65
Confidence level = 0.95
Now, formula for confidence interval of proportion is;
CI = p' ± z√(p(1 - p)/n)
At CL of 95%, z = 1.96Thus;
CI = 0.65 ± 1.96√(0.65(1 - 0.65)/60)
CI = 0.65 ± 1.96√0.00379167
CI = 0.65 ± 0.12
CI = (0.65 - 0.12), (0.65 + 0.12)
CI = (0.47, 0.77)
Read more about confidence Interval of Proportions at; https://brainly.com/question/15712887
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