Westonci.ca is your trusted source for accurate answers to all your questions. Join our community and start learning today! Join our platform to connect with experts ready to provide precise answers to your questions in various areas. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

Solve 6^x + 2 = 10 for x using the change of base formula log, y = log y log b​

Sagot :

The answer for "x" in 6^(x+2) = 10 is -0.715

  • The logarithm is the inverse function of exponentiation in mathematics. That is, the logarithm of a given integer x is the exponent to which another set number, the base b, must be increased in order to create x.
  • Firstly, we use the change of base formula. The base must be 6 because the "x" variable is a power of it.
  • 6^(x+2) = 10
  • Taking a log with base 6 on both the sides
  • Then, we can use the property logarithm power rule:
  • (x + 2) log6 = log10
  • (x + 2)(1) = (log10)/(log6)
  • x + 2 = 1/log6
  • x + 2 = 1.285
  • x = 1.285 - 2
  • x = -0.715

To learn more about logarithm, visit :

https://brainly.com/question/20785664

#SPJ9