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Solve 6^x + 2 = 10 for x using the change of base formula log, y = log y log b​

Sagot :

The answer for "x" in 6^(x+2) = 10 is -0.715

  • The logarithm is the inverse function of exponentiation in mathematics. That is, the logarithm of a given integer x is the exponent to which another set number, the base b, must be increased in order to create x.
  • Firstly, we use the change of base formula. The base must be 6 because the "x" variable is a power of it.
  • 6^(x+2) = 10
  • Taking a log with base 6 on both the sides
  • Then, we can use the property logarithm power rule:
  • (x + 2) log6 = log10
  • (x + 2)(1) = (log10)/(log6)
  • x + 2 = 1/log6
  • x + 2 = 1.285
  • x = 1.285 - 2
  • x = -0.715

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