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HOW MANY GALLONS OF A 90% ANTIFREEZE SOLUTION MUST BE MIXED WITH 90 GALLONS Of 10% ANTIFREEZE TO GET A MIXTURE THAT IS 80% ANTIFREEZE

Sagot :

630 gallons of 90% antifreeze has to be mixed.

Sum of values of two solutions = Value of mixture  

90% =0.9 unit value and amount x we get value 0.9x

10%= 0.1 unit value and amount 90 we get value =0.1*90=9

total mixture =0.80 value x+90 we get value 0.8*(x+90)

0.9x + 9 = 0.8(x + 90)  

0.9x + 9 = 0.8x + 90 x 0.8

0.9x – 0.8x = 72 – 9

0.1x = 63

x = 630

Hence, 630 gallons of 90% antifreeze has to be mixed.

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