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find the next three terms of the sequence 15,23,38,61​

Sagot :

a = 15

a4 = 61

difference between 2 consecutive terms (d)

= a2 - a = 23 - 15 = 8

Now,

Next three terms shall be a5, a6, a7.

a5 = a + 4d = 15 + 4×8 = 15 + 32 = 47

a6 = a + 5d = 15 + 5×8 = 15 + 40 = 55

a7 = a + 6d = 15 + 6×8 = 15 + 48 = 63

Hence, next three terms are 47, 55, 63.