At Westonci.ca, we make it easy for you to get the answers you need from a community of knowledgeable individuals. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

A speedboat moves west at 108 km/h for 22.0 min. It then moves at 60.0° south of west at 90.0 km/h for 10.0 min.

What is the average speed for the trip?


What is the magnitude of average velocity for the trip?


What is the direction of average velocity for the trip? Enter the angle in degrees where negative indicates north of west and positive indicates south of west.


Sagot :

Answer:

108 km/hr = 1.8 km/min

90 km/hr = 1.5 km/min

V1 = (-39.6, 0)

V2 = (-10.6, -10.6)         (10.6^2 + 10.6^2)^1/2 = 15    1.5 km/min * 10 min

V = (-50.2, -10.6)       final displacement vector

Total time = 22 + 10 = 32 min

S = (50.2^2 + 10.6^2)^1/2 = 51.3 km

Average speed = (1.8 * 22 + 1.5 * 10) / 32 = 1.71 km / min

Displacement = 51.3 km

Average velocity = 51.3 / 32 = 1.60 km/min

Direction = 10.6 / 50.2 = .211 or 11.9 deg S of W

Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.