Westonci.ca is the premier destination for reliable answers to your questions, brought to you by a community of experts. Get the answers you need quickly and accurately from a dedicated community of experts on our Q&A platform. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

I am struggling with transformations,rotation on a cartesian plane,how do we do it?​

Sagot :

Greetings from Brasil...

Translations

Just add or subtract an m value for all X coordinates as well as add or subtract an n value for all Y coordinates of the figure.

P(X; Y) → P'(X ± m; Y ± n)

If the figure has 3 points (A, B and C), we would be left with:

A(X, Y) ; B(X₂; Y₂) ; C(X₃; Y₃)

A(X, Y) → A'(X ± m; Y ± n)

B(X₂; Y₂) → B'(X₂ ± m; Y₂ ± n)

C(X₃; Y₃) → C'(X₃ ± m; Y₃ ± n)

in our example - see attached figure - let

m = 4

n = - 1

(these values of m=4 and n=-1 were chosen by me arbitrarily)

A(1; 2) → A'(1 + 4; 2 - 1) ⇒ A'(5; 1)

B(2; 3) → B'(2 + 4; 3 - 1) ⇒ B'(6; 2)

--------------------------------------------------------------------------

Rotations

The expression (formula) for rotation will be:

P(X; Y) → P'(Xcos θ - Ysen θ; Xsen θ + Ycos θ)

Let rotate 90° (counter-clockwise): cos 90 = 0 and sen 90 = 1, then

P(X; Y) → P'(-Y; X)

in our example - see attached figure

A(1; 2) → A''(-2; 1)

B(2; 3) → B''(-3; 2)

______________________________

see more at:

https://brainly.com/question/28354239

View image tomson1975
View image tomson1975