Greetings from Brasil...
Translations
Just add or subtract an m value for all X coordinates as well as add or subtract an n value for all Y coordinates of the figure.
P(X; Y) → P'(X ± m; Y ± n)
If the figure has 3 points (A, B and C), we would be left with:
A(X, Y) ; B(X₂; Y₂) ; C(X₃; Y₃)
A(X, Y) → A'(X ± m; Y ± n)
B(X₂; Y₂) → B'(X₂ ± m; Y₂ ± n)
C(X₃; Y₃) → C'(X₃ ± m; Y₃ ± n)
in our example - see attached figure - let
m = 4
n = - 1
(these values of m=4 and n=-1 were chosen by me arbitrarily)
A(1; 2) → A'(1 + 4; 2 - 1) ⇒ A'(5; 1)
B(2; 3) → B'(2 + 4; 3 - 1) ⇒ B'(6; 2)
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Rotations
The expression (formula) for rotation will be:
P(X; Y) → P'(Xcos θ - Ysen θ; Xsen θ + Ycos θ)
Let rotate 90° (counter-clockwise): cos 90 = 0 and sen 90 = 1, then
P(X; Y) → P'(-Y; X)
in our example - see attached figure
A(1; 2) → A''(-2; 1)
B(2; 3) → B''(-3; 2)
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see more at:
https://brainly.com/question/28354239
