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Sagot :
Answer is h(x) =[tex]\frac{1}{2}[/tex] cos ([tex]\frac{2}{3}[/tex]π +[tex]\frac{2}{3}[/tex]π ) - [tex]\frac{1}{2}[/tex]
∵The maximum point (- 2π. 3 )
minimum point (- π / 2 , - 4)
and h(x) = a cos (b x + c)+ d
∴ a + d = 3 d = - 1/ 2
⇒
-a + d = -4 a = 7 / 2
{solve the equation}
and -2πb + c = 0 b = 2 / 3
⇒
- ( π/ 2) b + c = λ c = 4 / 3 π
∴ h(x) =[tex]\frac{1}{2}[/tex] cos ([tex]\frac{2}{3}[/tex]π +[tex]\frac{2}{3}[/tex]π) - [tex]\frac{1}{2}[/tex]
Trigonometric functions are also known as Circular Functions can be simply defined as the functions of an angle of a triangle. It means that the relationship between the angles and sides of a triangle are given by these trig functions. The basic trigonometric functions are sine, cosine, tangent, cotangent, secant and cosecant
here detail explanation:
Sine Function
Sine function of an angle is the ratio between the opposite side length to that of the hypotenuse. From the above diagram, the value of sin will be:
Sin a =Opposite/Hypotenuse = CB/CA
Cos Function
Cos of an angle is the ratio of the length of the adjacent side to the length of the hypotenuse. From the above diagram, the cos function will be derived as follows.
Cos a = Adjacent/Hypotenuse = AB/CA
Tan Function
The tangent function is the ratio of the length of the opposite side to that of the adjacent side. It should be noted that the tan can also be represented in terms of sine and cos as their ratio. From the diagram taken above, the tan function will be the following.
Tan a = Opposite/Adjacent = CB/BA
Also, in terms of sine and cos, tan can be represented as:
Tan a = sin a/cos a
Secant, Cosecant and Cotangent Functions
Secant, cosecant (csc) and cotangent are the three additional functions which are derived from the primary functions of sine, cos, and tan. The reciprocal of sine, cos, and tan are cosecant (csc), secant (sec), and cotangent (cot) respectively. The formula of each of these functions are given as:
Sec a = 1/(cos a) = Hypotenuse/Adjacent = CA/AB
Cosec a = 1/(sin a) = Hypotenuse/Opposite = CA/CB
cot a = 1/(tan a) = Adjacent/Opposite = BA/CB
Note: Inverse trigonometric functions are used to obtain an angle from any of the angle’s trigonometric ratios. Basically, inverses of the sine, cosine, tangent, cotangent, secant, and cosecant functions are represented as arcsine, arccosine, arctangent, arc cotangent, arc secant, and arc cosecant.
Learn more about trigonometric function here: brainly.in/question/2706902
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