Westonci.ca offers quick and accurate answers to your questions. Join our community and get the insights you need today. Get immediate answers to your questions from a wide network of experienced professionals on our Q&A platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
Greetings from Brasil...
In a trigonometric function of Cosine, we have:
F(X) = ±A ± B.COS(MX + N)
where
A = move the graph up or down
B = change the amplitude
M = change period
N = move the graph left or right without distorting it
According to the statement, we don't have A and N, so
F(X) = ± B.COS(MX)
According to the graph presented, we have:
B = amplitude = 2.5 = 5/2
period = π
detail that
Period = 2π/M
π = 2π/M ⇒ M = 2
As B = 5/2 and M = 2, then
F(X) = (5/2)COS(2X)
(I used the cosine function, because in X = 0 Y will have a non-zero value, as we can see in the graph)
Thank you for visiting our platform. We hope you found the answers you were looking for. Come back anytime you need more information. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.