Answer:
[tex]\textsf{1.} \quad s=\dfrac{8r}{9}[/tex]
[tex]\textsf{2.} \quad s=4[/tex]
[tex]\textsf{1.} \quad x=y(w+z)[/tex]
[tex]\textsf{2.} \quad x=10[/tex]
Step-by-step explanation:
Question 1
1. Solve for s:
[tex]\implies 2r = \dfrac{5s}{2}-\dfrac{s}{4}[/tex]
[tex]\implies 2r = s\left(\dfrac{5}{2}-\dfrac{1}{4}\right)[/tex]
[tex]\implies 2r = s\left(\dfrac{10}{4}-\dfrac{1}{4}\right)[/tex]
[tex]\implies 2r = s\left(\dfrac{9}{4}\right)[/tex]
[tex]\implies 4(2r) = 9s[/tex]
[tex]\implies 8r = 9s[/tex]
[tex]\implies s=\dfrac{8r}{9}[/tex]
2. When r = ⁹/₂ :
[tex]\implies s=\dfrac{8\left(\frac{9}{2}\right)}{9}[/tex]
[tex]\implies \dfrac{8}{9} \times \dfrac{9}{2}[/tex]
[tex]\implies \dfrac{8 \times9}{9 \times2}[/tex]
[tex]\implies s=\dfrac{72}{18}[/tex]
[tex]\implies s=4[/tex]
Question 2
1. Solve for x:
[tex]\implies w=\dfrac{x}{y}-z[/tex]
[tex]\implies w+z=\dfrac{x}{y}[/tex]
[tex]\implies y(w+z)=x[/tex]
[tex]\implies x=y(w+z)[/tex]
2. When x = -8, y = -5, z = 6:
[tex]\implies x=-5(6+(-8))[/tex]
[tex]\implies x=-5(6-8)[/tex]
[tex]\implies x=-5(-2)[/tex]
[tex]\implies x=10[/tex]
