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The graph of y=
-2x²5x+2 is drawn below
Draw a suitable line to solve -2x² - 5x + 2 = -5


The Graph Of Y 2x5x2 Is Drawn Below Draw A Suitable Line To Solve 2x 5x 2 5 class=

Sagot :

Answer:

x = 1 and x = -3.5

Step-by-step explanation:

y = -2x² -5x + 2

-2x² -5x + 2 = -5

which means y = -5

Draw the line on y = -5 like the green line in the attached file

and see where this line intersects with the graph

the values are:

x = 1 and x = -3.5

View image munazzahy9

Answer:

Draw a line at y = -5.

x ≈ -3.5

x ≈ 1

Step-by-step explanation:

Given equation:

[tex]y = -2x^2 - 5x + 2[/tex]

This is the equation of the graphed parabola.

To solve the equation  [tex]-2x^2 - 5x + 2 = -5[/tex]  draw a line at y = -5 and find the points of intersection of the two graphed equations.

From inspection of the graph, the x-values of the points of intersection are:

  • x ≈ -3.5
  • x ≈ 1

Solving algebraically

Add 5 to both sides of the equation:

[tex]\implies -2x^2-5x+2+5=-5+5[/tex]

[tex]\implies -2x^2-5x+7=0[/tex]

Factor out -1 from the left side:

[tex]\implies -1(2x^2+5x-7)=0[/tex]

Divide both sides by -1:

[tex]\implies 2x^2+5x-7=0[/tex]

Find two numbers that multiply to -14 and sum to 5:  7 and -2

Rewrite b as the sum of these two numbers:

[tex]\implies 2x^2+7x-2x-7=0[/tex]

Factor the first two terms and the last two terms separately:

[tex]\implies x(2x+7)-1(2x+7)=0[/tex]

Factor out the common term (2x + 7):

[tex]\implies (x-1)(2x+7)=0[/tex]

Apply the zero-product property:

[tex](x-1)=0 \implies x=1[/tex]

[tex](2x+7)=0 \implies x=-\dfrac{7}{2}=-3.5[/tex]

View image semsee45