Welcome to Westonci.ca, the Q&A platform where your questions are met with detailed answers from experienced experts. Experience the ease of finding quick and accurate answers to your questions from professionals on our platform. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

Consider any subset of the real numbers that consists only
of negative numbers. What can you conclude about whether the set is closed
under multiplication?
Explain.

Sagot :

Answer:  Not closed under multiplication

====================================================

Explanation:

Pick any two negative numbers that you want.

I'll go for -3 and -5

They multiply to (-3)*(-5) = 15 which is a positive number. The two negatives cancel out to form a positive.

This is an example to show that multiplication is not closed for this subset of the real numbers. We consider it to be closed if the result of any two negative numbers multiplied would get us some other negative number.

In a sense, this is the complete opposite of closed since the result is never negative.

Here's an example of a set that is closed under multiplication: integers

Picking any two integers and multiplying them together gets us some other integer. Each item is found in the same set, i.e. the result never leaves or goes outside the set.