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The emission spectrum of cesium contains two lines whose frequencies are (a)
3.45 xx 10¹4 Hz and (b) 6.53 xx 10¹4 Hz. What are the wavelengths and energies per
photon of the two lines? What color are the lines?

Sagot :

pstnonsonjoku

The lines are violet and blue respectively.

What is the energy?

We know that the energy of the photon could be obtained by the use of the equation;

E = hf

E = energy

h = Plank's constant

f = frequency

For the first line;

E = 6.6 * 10^-34 Js * 3.45 x 10^14 Hz = 2.3 * 10^-19 J

Given that;

E = hc/λ

λ = hc/E

λ = 6.6 * 10^-34 * 3 * 10^8/2.3 * 10^-19

λ = 8.61 * 10^-7 m or 861 nm

The color is violet

For the second line;

E = 6.6 * 10^-34 Js * 6.53 xx 10^14 Hz

E = 4.3 * 10^-19 J

E = hc/λ

λ = hc/E

λ =  6.6 * 10^-34 * 3 * 10^8/4.3 * 10^-19

λ = 4.60 * 10^- 7 m or 460 nm

The color is blue

Learn more about emission spectrum:https://brainly.com/question/13537021

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