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9. If h(x)=√x-3 +5, then for what value(s) of 10
x does h(x) = 3?

Sagot :

Answer:

There are no values of x that make this equation true.

Step-by-step explanation:

We know h(x)=[tex]\sqrt{x-3} +5[/tex]

So lets substitute h(x) for 3

3=[tex]\sqrt{x-3}+5[/tex]

We are going to then subtract 5 from each side leaving us with

-2=[tex]\sqrt{x-3}[/tex]

We then need to get rid of the square root, so we will square both sides. which gives us

4=x-3

We then need to subtract 3 from both sides which leaves us with

x=1

However, when you substitute 1 for x into the original equation, you get

h(x)=[tex]\sqrt{-2}+5[/tex]

Which is not equal to 3

Therefore, there are no values of x that make this equation true.

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