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Sagot :
The probability that 3 out of 5 offspring from the cross will be brown and short does not exist or is zero.
Dihybrid crossing
A represents brown and a represents white.
B is tall while b is short.
AaBb x Aabb
Offspring
A_B_ (brown and tall) = 6/16 or 3/8
A_bb (brown and short) = 6/16 or 3/8
aaB_ (white and tall) = 2/16 or 1/8
aabb (white and short) = 2/16 or 1/8
In other words, the probability of producing offspring that are brown and short is 3/8.
Thus, the probability that 3 out of 5 offspring from the cross will be brown and short does not exist or is zero.
More on dihybrid crosses can be found here: https://brainly.com/question/1185199
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